| Author | Message | ||||||||||||||||||||||||||||||||||||||||||
     Elijah Unregistered guest |
What about coiling insulated copper wire around the neodymium magnets to create a electromagnet making the steel balls go faster without adding more magnets | ||||||||||||||||||||||||||||||||||||||||||
| Simon Quellen Field (sfield) New member Username: sfield Post Number: 116 Registered: 12-2004 |
Try it, and report your results here! | ||||||||||||||||||||||||||||||||||||||||||
| Elijah Unregistered guest |
I bought the enamled wire yesterday, but I would like to know which is the greater factor in an elctromagnet Volts or Amps? | ||||||||||||||||||||||||||||||||||||||||||
| marusushi Unregistered guest |
I believe it is amps, but too many amps can fry the wire and destroy your magnets. | ||||||||||||||||||||||||||||||||||||||||||
| Elijah Unregistered guest |
Thats what I thought but I wasnt Sure | ||||||||||||||||||||||||||||||||||||||||||
| Simon Quellen Field (sfield) New member Username: sfield Post Number: 121 Registered: 12-2004 |
Current and the number of turns of wire is what determines the strength of a coil. But if you raise the voltage, more current will go through the wire. | ||||||||||||||||||||||||||||||||||||||||||
| Elijah Unregistered guest |
thanx | ||||||||||||||||||||||||||||||||||||||||||
| Anonymous |
gauss rifle problem coil wound around thin aluminum tube with steel rod bearing in it which becomes the em. one end of tube is open, other has a strong, factory build em which repels the bearing em. problem is that the rod bearing em is attracted to the factory em and wont always shoot out the tube. i can decrease the strength of the factory em and increase the other em to create launch power but it doesnt have the zoom i got out of one great, unsurpassed test due to above problem. should i adjust the timing of the pulses, strength, rod size, or do i have a different problem? help would be greatly appreciated.  | ||||||||||||||||||||||||||||||||||||||||||
| bill nye Unregistered guest |
if i used the principle of linear magnetic acceleration and used thousand of magnets and ball bearings, instead of the 4 shown in most sci-sites, would i eventually hit C(assuming the magnets/marbles don't desintagrate on impact)? | ||||||||||||||||||||||||||||||||||||||||||
| lysdexia Unregistered guest |
disintegrate Simon, shame on you for making him blow his money. bill, no you wouldn't. And your ball wouldn't either.. at least that you could tell. | ||||||||||||||||||||||||||||||||||||||||||
| bill nye Unregistered guest |
all right, scrap light speed. how about mach. is that reasonable for a garage goal? | ||||||||||||||||||||||||||||||||||||||||||
| Simon Quellen Field (sfield) Senior Member Username: sfield Post Number: 309 Registered: 12-2004 |
The 1 foot long Gauss Rifle in my book fires the steel ball at about 15 feet per second. To double the speed to 30 feet per second, you would use 16 magnets on a 4 foot guide. To double the speed again to 60 feet per second, you would use 64 magnets on a 16 foot guide. You can keep going in this fashion to get the speed you want. An air rifle shoots BBs at between 500 to 1250 feet per second. A center fire rifle usually exceeds 2000 feet per second, often exceeding 3000 fps. To see how we can make a Gauss Rifle that will achieve the velocities of a cheap rifle, we can construct the following table:
So, with over a quarter of a million magnets, a half a million steel balls, and 12 and a half miles of track, at an estimated cost of $786,432.00 we could construct a Gauss Rifle that would be the equal of a $150 rifle purchased at K-mart. If you simply want to break the sound barrier, something around 10,000 magnets will probably get close. | ||||||||||||||||||||||||||||||||||||||||||
| MadScientist (madscientist) Intermediate Member Username: madscientist Post Number: 22 Registered: 4-2005 |
Whew. I'd LOVE to see THAT one fire! | ||||||||||||||||||||||||||||||||||||||||||
| Billy Ward (Satan_imp2) New member Username: Satan_imp2 Post Number: 1 Registered: 5-2005 |
Just for inventive thought, what if the magnets were replaced with electromagnets; that briefly turned off after being struck?? In this idea would the end result not be amplyfied condiserably? After the initial strike, the electromagnet would turn off, and in turn, not bring about any drag to the next 2 bearings. Hence a greater accumulation of force.... I think.. Any thoughts? | ||||||||||||||||||||||||||||||||||||||||||
| MatthewColt22 Unregistered guest |
That would be one way to increse the exit velocity for sure, in fact i am also building a gauss rifle in a similar fassion, if you use iron rods that are formed into electromagnets and use them as your magnets and devise a way to turn them off once the magnets hit them, then yes you could have a very powerful gauss rifle on your hands. My origional plans dident include cutting the power, but i might try your idea, seems like i could work | ||||||||||||||||||||||||||||||||||||||||||
| Simon Quellen Field (Sfield) Senior Member Username: Sfield Post Number: 435 Registered: 12-2004 |
You can turn on the spelling checker in your profile if you like. | ||||||||||||||||||||||||||||||||||||||||||
| Mike Manchak Unregistered guest |
do you think small cylinders could replace the ball bearings in a tube for this type of mechanism, due to the increased contact area of the ends of the cylinders, would this make the kinetic energy transfer faster, resulting in a faster exit velocity? any responces would be greatly appriciated, thanks | ||||||||||||||||||||||||||||||||||||||||||
| Joel Unregistered guest |
What if you used gravitational potential energy to assist in launching a projectile out of a gauss gun? For example, mounting it on an angle that just barely allows the magnets to hold the bearings in place. | ||||||||||||||||||||||||||||||||||||||||||
| Simon Quellen Field (Sfield) Senior Member Username: Sfield Post Number: 478 Registered: 12-2004 |
The magnets can hold the balls vertically. That's how I normally carry a loaded Gauss Rifle -- aimed at the ground. The 4 magnet Gauss Rifle fires the ball at about 4.5 meters per second. A steel ball dropped from a height accelerates at 9.8 meters per second per second. It thus takes .46 seconds for a falling ball to reach a velocity of 4.5 meters per second. To find the height it fell to reach that speed, we multiply the square of the time by half the acceleration. So .46 seconds times .46 seconds times 9.8 meters per second per second divided by 2 is about 1.04 meters. If you drop a steel ball from 1.04 meters, it will reach a speed of 4.5 meters per second before it hits the ground. So, the Gauss Rifle adds the same energy as holding the ball about a meter above the ground. You can do away with the Gauss Rifle by holding the ball an additional meter above the ground. | ||||||||||||||||||||||||||||||||||||||||||
| Anonymous Unregistered guest |
Looks like it'd still be of more fun designing nuclear particle projectors. | ||||||||||||||||||||||||||||||||||||||||||
| Simon Quellen Field (Sfield) Senior Member Username: Sfield Post Number: 486 Registered: 12-2004 |
We have several on the web site already, but more nuclear particle projectors are always good. Post your descriptions and pictures here. | ||||||||||||||||||||||||||||||||||||||||||
| Anonymous |
Can anyone explain the transfer of energy and momentum between the magnet and the ball in the Gauss Rifle? if the magnet is fixed, what would make the ball move? or must it have a small impulse (kick) and must not be completely fixed. can this be a factor for increasing speed (J=Ft)? can we eliminate the need for a second ball next to the one in ground state? does anyone have the momentum equation for the 4 magnet rifile or for Newton's Toy/pendulum? thanks | ||||||||||||||||||||||||||||||||||||||||||
| Anonymous Posted From: 68.111.171.253 |
the magnet doesnt have to move. it transfers the energy to the ball bearings next to it. | ||||||||||||||||||||||||||||||||||||||||||
| Dhruv Chopra (Unregistered Guest) Unregistered guest Posted From: 164.100.35.60 |
Hi! Can anyone guide me to how I can derive an equation for the acceleration or the velocity of the final ball? Please. Thanks. |
