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Andrew
Posted on Friday, July 23, 2004 - 9:38 am:   Edit PostDelete PostView Post/Check IPPrint Post   Move Post (Moderator/Admin Only)Ban Poster IP (Moderator/Admin only)

Hi Simon,
I have a question that's been bugging me. In your chapter on thermodynamics, you say that "Hydrogen will burn in air at concentrations ranging from 4% to 75% by volume" and "Hydrogen will explode in air at ratios of 13% to 59%".

When you burn hydrogen, it combines with oxygen to make water. Water is H2O, so that means that it is 2/3 hydrogen and 1/3 oxygen. This also has to be the perfect burning ratio, since there will be no 'ingredients' left over. If I mixed these two gases at this ratio and ignited them, would the mixture burn or explode? And what would this 'perfect ratio' be if I mixed Hydrogen with air (so that if I ignited it in a closed container, there would be no left over Hydrogen or Oxygen)? Thanks!
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Simon Quellen Field (Sfield)
Posted on Friday, July 23, 2004 - 11:34 am:   Edit PostDelete PostView Post/Check IPPrint Post   Move Post (Moderator/Admin Only)Ban Poster IP (Moderator/Admin only)

Dry air is 20.95% oxygen by volume.

This goes down as the air gets more humid, but we can use 20% as a nice
round figure. That means 1 part oxygen and 4 parts other gasses.
Since we have one part oxygen, we add two parts hydrogen to get a
perfect mixture. Now there are seven parts in total (1 oxygen, 2 hydrogen,
and 4 other gasses). Two of the seven are hydrogen, so we have 28%
hydrogen by volume.

28% is between 13% and 59%, so we conclude that it will explode.
Removing the other gasses will not affect whether it will explode or not.
Thus, a mixture of two parts hydrogen to one part oxygen will explode.
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Andrew
Posted on Friday, July 23, 2004 - 2:34 pm:   Edit PostDelete PostView Post/Check IPPrint Post   Move Post (Moderator/Admin Only)Ban Poster IP (Moderator/Admin only)

Ok, that makes sense, thanks for your help!

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